2.
The hybridization of atomic orbitals of nitrogen
in NO, NO, and NH are:
1) sp, sp3 and sp² respectively
2) sp, sp2 and sprespectively
3) sp?, sp and sp’ respectively
4) sp, sp and sprespectively
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Answer:
(a) The electronic configuration represents
2s22p5= fluorine = most electronegative element
3s23p5 = chlorine
4s24p5 = bromine
5s25p5 = iodine
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