Chemistry, asked by saisathwikpabba038, 7 months ago

2.
The hybridization of atomic orbitals of nitrogen
in NO, NO, and NH are:
1) sp, sp3 and sp² respectively
2) sp, sp2 and sprespectively
3) sp?, sp and sp’ respectively
4) sp, sp and sprespectively​

Answers

Answered by asmithakur635
1

Answer:

(a) The electronic configuration represents

2s22p5= fluorine = most electronegative element

3s23p5 = chlorine

4s24p5 = bromine

5s25p5 = iodine

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