Question

2. The inner diameter of a cylindrical wooden pipe is 24 cm and its outer diameter is
28 cm. The length of the pipe is 35 cm. Find the mass of the pipe, if I cm' of wood
a mass of 0.6 g​

Answer 1

Step-by-step explanation:

Find the radius:

r1 = 28 ÷ 2 = 14 cm

r2 = 24 ÷ 2 = 12 cm

Find the volume of the wood:

Volume = πh(r1² - r2²)

Volume = π(35)(14² - 12²)

Volume = 5720 cm³

Find the mass of the pipe:

1 cm³ = 0.6g

5720 cm³ = 0.6 x 5720 = 3432g or 3.432 kg