Question

2. The inner diameter of a cylindrical wooden pipe is 24 cm and its outer diameter is
28 cm. The length of the pipe is 35.cm. Find the mass of the pipe, if 1 cm of wood has
a mass of 0.6 g​

Answer 1

FINAL ANSWER:-

mass of the pipe = $3432 g$     or     $3.432 kg$

GIVEN:-

diameter of a cylindrical wooden pipe = r2 = $\frac{24}{2}$ cm

its outer diameter = r1 = $\frac{28}{2}$ cm

The length of the pipe = h = 35

1 cm of wood has  a mass of 0.6 g​

TO FIND:-

the mass of the pipe

FORMULA USED:-

πhr²1-πhr²2      or     πh(r²1-r²2)       [Volume of cone]  

SOLUTION:-

volume of hollow cylinder = πhr²1-πhr²2 OR  πh(r²1-r²2)

                                           =$\frac{22}{7}*35(14^{2}-12^{2})$

                                           =$\frac{22}{7}*35(196-144)$

                                           =$\frac{22}{7}*35*52$

                                           =22×5×52

                                           =5720

∴ weight of cylinder =5720 cm³ × 0.6g

                                = 3432 g   or  3.432 kg