Question

2. The L.C.M. and H.C.F. of two numbers are 1760 and 32, respectively. If one of the numbers
is 160, find the other.
is 120. find their H.C.F.​

Answer 1

$\large \underline{\pmb{\frak{Given....}}}$

The LCM and HCF of two numbers are 1760 and 32. One of the number is 160.

$\large \underline{\pmb{\frak{To\: find....}}}$

We have to find the other number.

$\large \underline{\pmb{\frak{Solution....}}}$

Given that :

$\qquad$ ❍ LCM = 1760

$\qquad$ ❍ HCF = 32

So, let the other number be x.

We know that,

• Product of two numbers = LCM × HCF

Now, finding x :

$\qquad \sf➯~~160(x) = 1760(32)$

$\qquad \sf➯~~160x = 56320$

$\qquad \sf➯~~x = \dfrac{56320}{160}$

$\qquad \sf➯~~x = 352$

_________________________

❍ Therefore, the other number is 352.