Question

2) The largest fourdigit number which when divided
by 4, 7 and
13 leaves a remainder of 3 in each case
Find the number​

Answer 1

Answer:

The answer is 9831

Step-by-step explanation:

Prime factors of 4,7 and 13

4=2×2

7 and 13 are prime numbers  

LCM  (4,7,13)=36

We know that, the largest 4 digit number is 9999.

Step 1 : Divide 9999 by 364, we get  

9999/364  

=171  

Step 2: Subtract 171 from 9999  

9999−171=9828

Since a remainder of 3 is to be left  

9282+3=9831  

Therefore, 9831 is the number.