Question

2. The LCM of two numbers is 630 and their HCF is 15. If one number is 105, find the other
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Answer 1

LCM × HCM = a × b

630 × 15 = 105 × b

9450 = 105 × b

b = $\frac{9450}{105}$

b = 90

The another number is 90

hope it helps ☺️

Answer 2

90

Step-by-step explanation:

Product of two numbers is always equal to product of their LCM and HCF So in the given question

one no. is given I.e. 105 so

Let's assume another no. A

hence LCM x HCF = 105 x A

630 x 15 = 105 x A

9450 = 105 x A

9450/105 = A

90.

so the other no. is 90.