Question

2. The length, breadth and height of a room are 5 m, 4 m and 3 m respectively. Find me
cost of white washing the walls of the room and the ceiling at the rate of 7.50 per m. ​

Answer 1

Answer:-

Total required cost is 555 rupees.

Step by Step Explaination:-

Given:-

Dimensions of the room are :–

Length (l) = 5m

Breath (b) = 4m

Height (h) = 3m

Logic:-

As the room is cuboidal and according to the question we need to find the surface area for whitewashing.

Therefore:-

Lateral surface area of the walls of room

=> 2 × h × ( l + b )

=> 2 × 3 × ( 5 + 4 )

=> 6 × 9

=> 54 m²

And area of the ceiling wall = l × b

=> 5 × 4 m²

=> 20 m²

Total area of the walls required for whitewashing = area of four walls of room + area of the ceiling wall

=> 54m² + 20m²

=> 74m²

Also we have:-

Cost of whitewashing 1 m² = 7.50/-

Cost of whitewashing 74 m² = 74 × 7.50/-

Cost of whitewashing 74 m² = 555 /-.

Hence:-

Total required cost is 555 rupees.

#answerwithquality #BAL

Answer 2

Answer:

• Total cost required for white washing the walls of the room = Rs. 555

Step-by-step explanation:

Given:

• Breadth of a room (b) = 4m
• Length of a room (l) = 5m
• Height of a room (h) = 3m
• Cost of white washing the walls = Rs - 7.50 per m²

To find:

• Cost of white washing the walls of the room and the ceiling.

It is given that four walls and the ceiling of the room are to be white-washed. The floor of the room is not to be white-washed.

So, Area for whitewashing = Area of the roof + lateral surface area (4 walls)

⇒ Area for whitewashing = lb + 2h(l + b)

⇒ Area for whitewashing = 5 × 4 + 2 × 3(5 + 4)

⇒ Area for whitewashing = 20 + 6 × 9

⇒ Area for whitewashing = 74 m²

Now, cost of white washing the walls of the room and the ceiling = Rs. 7.50 per m².

So, Cost of 74 m² = 74 × 7.50 = Rs. 555.

Hence, total cost required for white washing the walls of the room = Rs. 555.

#answerwithquality

#BAL