Question

2.
The length, breadth and height of a room are 5 m, 4 m and 3 m respectively. Find
the cost of white washing the inner of the room and ceiling at the rate of 50
per square metre.
3.
Find the total surface area of a closed cardboard box of length 0.5 m, breadth
25 cm and height 15 cm.
238​

Answer 1

Answer:

2.) Rs.3700;3.) 4750m²

Step-by-step explanation:

2.) length=5m

breadth=4m

height=3m

surface area of four walls=2(l+b)*h=2(5+4)*3=6(9)=54m²

area of ceiling=area of rectangle=lb=5*4=20m²

total area to be white washed=54+20=74m²

U have sent it in wrong way , it is rs.50 or paise 50, ok i will send in both ways.

first way-

(74*50)Rs.=Rs.3700

second way-

(74*50)paise=3700p=Rs.37

but first one is the most appropriate.ok

3.)length=0.5m=50cm

breadth=25cm

height=15cm.

total surface area of cuboid=2(lb+bh+hl)=2[{50*25}+{25*15}+{15*50}]

=2[1250+375+750]=2*2375=4750m².

ok thanks.

pls mark me the bbrainliest. these answers are correct.