2. The length of a hall is 8 m and its width is 13.5 m. Find the least number of square tiles each of 25 cm recuired to cover the floor [ [3]
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Answer:
Length of hall =18m=1800cm
Breadth of hall =13.5m=1350cm
Width of margin =1.5m=150cm
Now, EFGH is the required area of hall flow to be filled.
Now, length of floor =1800−(2×150)=1500cm
Breadth of floor =1350−(2×150)=1050cm
∴ Area EFGH=1500×1050=1575000cm2
Area of 1 square tile =25×25=625cm2
Number of tiles =Areaof1tileAreaEFGH=6251575000=2520
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