2) The length of a rectangle exceeds
its breadth by 9cm. if the length and
breadth each increased by 3 cm. the
area of the new rectangle will be
84 cm? more than that of the given
rectangle find the length and breadth of
the rectangle
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let the breadth be x
length: x+9 , breadth: x
length and breadth are incresed by 3 so,
length: x+9 +3 = x+12 ,breadth: x+3
Gn: the area of the new rectangle = 84 sq. cm
Equation:
(x+12)(x+3)= 84+ x(x+9)
x2 + 15x + 36 = 84 + x2 +9x
if we transpose x2to the opposite side then it becomes x2
x2 x2 + 15x + 36 = 84 + 9x
Now it becomes 15x+36 = 84 +9x
If we transpose 9x to the opposite side it becomes 15x +36 9x = 84
6x +36 = 84
6x = 84 36
6x= 48
x=48/6
x=8
length : 8+9 = 17
breadth= 8
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