Question

2. The lengths of the diagonals of a rhombus ure 16 cm and 12cm. The length of each side of the rhombus is​​

Answer 1

Answer: 10 cm is the answer of the question

Step-by-step explanation:

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Answer 2

Let the side of rhombus be a cm.

Diagonals of rhombus are perpendicular to each other and bisect each other,

So, by Pythagoras theorem,

${a}^{2} = {( \frac{16}{2}) }^{2} + { (\frac{12}{2} )}^{2}$

${a}^{2} = {8}^{2} + {6}^{2}$

${a}^{2} = 64 + 36 = 100$

$a = \sqrt{100} = 10$

Each side = 10cm

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