2) The lid of a rectang lar bor of side yo cm dy 10 cm
seculed all round with tape. What is the lenght
of tape required ?
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Answer:
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Explanation:
Since the lid of a box is rectangular and is sealed all around with tape, hence, the required tape length will be equal to the perimeter of the rectangle = 2 (Length + Breadth)
Now, the total length of the tape required = Perimeter of the rectangle
From the figure, Length = 40 cm, Breadth = 10 cm.
Thus, by substituting in the formula,
⇒ Perimeter = 2 (Length + Breadth)
⇒ 2 (40 + 10)
⇒ 2 × 50 = 100 cm
Thus, the tape length required is 100 cm.
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