Question

2. The lid of a rectangular box of sides 40 cm by 10 cm is sealed all around with tape. What is the length of the tape required? Don't spam

Answer 1

Since the lid of a box is rectangular and is sealed all around with tape, hence, the required tape length will be equal to the perimeter of the rectangle = 2 (Length + Breadth)

Now, the total length of the tape required = Perimeter of the rectangle

From the figure, Length = 40 cm, Breadth = 10 cm.

Thus, by substituting in the formula,

⇒ Perimeter = 2 (Length + Breadth)

⇒ 2 (40 + 10)

⇒ 2 × 50 = 100 cm

Thus, the tape length required is 100 cm.

Answer 2

SOLUTION -

GIVEN -
Length of the rectangular box =  40 cm
Breadth of the rectangular box =  10 cm

AREA OF RECTANGLE = Length x Breadth
                                      = 40 x 10
                                      = 400 cm^2

The length of the tape required to seal the lid of a rectangular box of sides 40 cm by 10 cm with tape will be 100 cm^2 .

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