2.
The marked price of a water cooler is 5,400. The shopkeeper offers an off season
discount of 20% on it. Find its selling price.
Answers
Answered by
3
Answer:
5400×(20/100) =1080
5400 - 1080 = 4230
Selling price=4230
Answered by
17
Answer:
Selling Price = Rs 4320.
Step-by-step explanation:
Given,
- Market Price = 5400 rupees
- Discount = 20% = 20/100 = 0.2
Then,
Discount Price = Discount × Market Price
⇒ Discount Price = 5400 × 0.2
⇒ Discount Price = 1080 rupees
Therefore,
Selling Price = Market Price - Discount Price
⇒ Selling Price = 5400 - 1080
⇒ Selling Price = 4320 rupees
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