Question

2. The molar conductance at infinite dilution for Nal ,CH₃COONa and (CH₃COO)₂ Mg are 10.59, 7.10 and 16.58 Scm² mol⁻¹ respectively at 298 K. Calculate the molar conductance of MgI₂ at infinite dilution.

Answer 1

Answer:

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Explanation:

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Answer 2

The molar conductance of MgI₂ at infinite dilution 9.6Scm² mol⁻¹.

Given:

The molar conductance at infinite dilution for Nal, CH₃COONa and (CH₃COO)₂ Mg are 10.59, 7.10 and 16.58 Scm² mol⁻¹ respectively at 298 K.

To Find:

The molar conductance of MgI₂ at infinite dilution.

Solution:

To find the molar conductance of MgI₂ at infinite dilution we will follow the following steps:

As we know,

MgI2 molar conductance is calculated by the formula = molar conductance of (CH₃COO)₂Mg + 2× (molar conductance of Nal - molar conductance of CH₃COONa).

Because MgI2 = (CH₃COO)₂ Mg + 2(Nal - CH₃COONa) as:

MgI2 -----> Mg2+ 2I-.

CH3COONa ------> CH3COO- + Na+

(CH3COO)2 Mg------> 2CH3COO- + Mg2+

Now,

Putting values in the above formula we get,

Molar conthe ductance of MgI2 = 16.58 + 2(10.59-7.10) = 16.58 -2(3.49) = 16.58 - 6.98 = 9.6Scm² mol⁻¹.

Henceforth, the molar conductance of MgI₂ at infinite dilution Is 9.6Scm² mol⁻¹.