Question

2. The moment of a force of 25 N about a point is
2.5 N m. Find the perpendicular distance of force
from that point.
Ans. 10 cm​

Answer 1

$\bigstar$ Given

The moment of force of 25 N about a point is 2.5 N m

$\bigstar$ To Find

The perpendicular distance of force from that point

$\bigstar$ Solution

We know that

$\rm \longrightarrow M=Fd$

Here

• M = moment of force
• F = force applied
• d = perpendicular distance

According to the question

We are asked to find the  perpendicular distance of force from that point

Given that

The moment of force of 25 N about a point is 2.5 N m

Hence

• Moment of force = 2.5 N m
• Force applied = 25 N

Substituting the values

We get

$\blue{\rm \longrightarrow 2.5=25 \times d}$

$\rm \longrightarrow d=\dfrac{2.5}{25} \ m$

$\green{\rm \longrightarrow d=0.1 \ m}$

Converting m → cm

Hint

multiply the length value by 100

Hence

We get

$\rm \longrightarrow d=0.1 \times 100 \ cm$

$\pink{\rm \longrightarrow d=10 \ cm}$

Therefore

Perpendicular distance = 10 cm

Answer 2

Answer:

10 cm

Explanation:

hope it helps you friend