Question

2. The motion of a particle moving along x-axis is 6
dv
represented by the equation - 6-3V, where
dt
is in m/s and t is in second. If the particle is at
rest att0. then
(1) The speed of the particle is 2 m/s when the
acceleration of particle is zero
(2) After a long time the particle moves with a
constant velocity of 2 m/s
(3) The speed is 0.5 m/s, when the acceleration is
half of its initial value
(4) The magnitude of final acceleration is 6 m/s2​

Answer 1

Explanation:

Given:dv/dt=6-3v=a

a) when, a=0

6-3v=0

v=6/3=2m/s