(2) The number of boys and girls in a class are in the ratio 14:10. The number of boys is 8 more than the numbers of girls. What is the total class strength?
Answers
Answer:
In the figure, the lines PQ and MS are parallel. QT and RS are also parallel. If <TQR = 80* and <M = 60",
A. Find the measures of the other two angles of triangle MTQ.
B. What is the measure of <PQM? Explain the method used.
C. Which among the following based on parallel lines can used to find the measure of <R?
1. Corresponding angles are equal.
2. Alternate angles are equal.
3. Co-interior angles are supplementary.
4. Co-exterior angles are supplementary.
Answer:
Let the number of boys be 7x and that of girls be 5x.
According to the given condition, we have
Number of boys = Number of girls +8
⇒7x=5x+8
⇒7x−5x=8 ....[Transposing 5x to LHS]
⇒2x=8
⇒x=
2
8
=4
Therefore, number of boys =7×4=28 and number of girls =5×4=20
So, total number of children in the class =28+20=48.
Hence, the class strength is 48.
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