Question

2. The number of electrons in a dipositive ion of an
element X is 18. If the mass number of X is 4 units
more than twice the number of electrons of its
ion, calculate the number of protons, electron and
neutrons in X.​

Answer 1

Answer:

more than 4 okyhuhttfgdd

Answer 2

is 2, 8, 14 and its ionic weight is 58 a.m.u. The number of neutrons in its nucleus would be:

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ANSWER

e = (2 + 8 + 14) = 24

Here, mass number : A = 58

Z = No. of protons = No. of electrons in the neutral atom = 24 +2 = 26

Mass Number = 58

No. Of Neutrons = Mass No. - Atomic No. = 58 - 26 = 32