Question

2.
The number of ion s present in 1 ml of O.IM
CaCl solution is
1. 1.8x1020
2. 6.0 *1020
3. 1.8x1019
4. 1.8x1021​

Answer 1

0.1M solution means that you have 0.1 mol of CaCl2 in 1000mL solution 

But CaCl2 ↔ C+ 2+ + 2Cl- = 3 ions / molecule 

Therefore the 0.1M CaCl2 solution = 0.3M in respect of ions. 

You have 0.3 mol ions in 1000 mL solution 

You have 0.3/1000 = 0.0.0003 mol ions in 1 mL solution 

Number of ions: 

1 mol of ions = 6.022*10^23 ions 

0.0003 mol ions = (0.0003)*(6.022*10^23) = 1.81*10^20 ions.

I hope you understand.

Answer 2

0.1M solution means that you have 0.1 mol of CaCl2 in 1000mL solution

But CaCl2 ↔ C+ 2+ + 2Cl- = 3 ions / molecule

Therefore the 0.1M CaCl2 solution = 0.3M in respect of ions.

You have 0.3 mol ions in 1000 mL solution

You have 0.3/1000 = 0.0.0003 mol ions in 1 mL solution

Number of ions:

1 mol of ions = 6.022*10^23 ions

0.0003 mol ions = (0.0003)*(6.022*10^23) = 1.81*10^20 ions.

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