Question

2. The number of marbles with A and B are in the ratio of
10:11. Which of the following cannot be a possible
number of marbles with A and B together?
(A) 189 (B) 210 (C) 231 (D) 153​

Answer 1

Given:

The number of marbles with $A$ and $B$ are in the ratio $10:11$

To find:

Among the given options which cannot be a possible number of marbles with $A$ and $B$ together.

Solution:

Let number of marbles with $A$ is $10k$ and number of marbles with $B$ is $11k$, where $k$ is any natural number.

∴Number of marbles with $A$ and $B$ together is $10k+11k=21k$.

Hence, number of marbles with $A$ and $B$ together should be multiple of $21$.

From the given options, the only option which is not multiple of $21$ is option $(D) 153$, rest all are multiple of

Hence, option $(D) 153$ cannot be a possible number of marbles with $A$ and $B$ together.