2. The number of students in two classes are in ratio
2:3. If 12 students increased in each class this ratio
changes to 8:11 the total number of students in
both classes previously is
Answers
Step-by-step explanation:
the no. of students in two class is in ratio 2:3
the no of students =. 2x, 3x
if 12 students increase in each class then no. of students = 2x + 12 , 3x + 12
given , 2x + 12 = 8x , 3x + 12 = 11x
therefore, 2x + 12 = 8x
12 = 8x - 2x.
12 = 6x
x = 12/6 = 2
since , x = 2
the total no. of students previously in both classes is = 2x + 3x = 2*2 + 3*2 = 4 + 6 = 10
Total Students = 90
Step-by-step explanation:
Given:
- Ratio of number of students in two classes are 2 : 3.
- After increasing 12 students to each class ratio becomes 8 : 11.
To Find:
- What is the total number of students in both classes previously ?
Solution: Let x be the common in given ratios. Therefore,
Ratio of students in each class = 2x and 3x
[ Now 12 students increased in both the classes ]
- Class¹ = (2x + 12) students
- Class² = (3x + 12) students
A/q
- After increasing 12 students to each class ratio becomes 8 : 11.
Let y be the common in ratios after the students increased.
So, Ratio = 8y and 11y
∴ 2x + 12 = 8y and 3x + 12 = 11y
Now let's solve the both
2x + 12 = 8y
2x = 8y – 12
x = (8y – 12/2).....(1)
and
3x + 12 = 11y
3(8y – 12/2) + 12 = 11y
24y – 36/2 + 12 = 11y
24y – 36 + 24/2 = 11y
24y – 12 = 22y
24y – 22y = 12
2y = 12
y = 6
Now putting the value of y in equation 1.
x = 8(6) – 12/2
x = 48 – 12/2
x = 36/2
x = 18
So number of studens in each class were
2x = 2(18) = 36 students
3x = 3(18) = 54 students
Total students = 36 + 54 = 90 students
[ For Verification ]
Ratio was 2 : 3
➮ 36/54 = 2/3 or 2 : 3 { cut by 18 }
and after increasing 12 students ratio was 8 : 11
➮ 36 + 12/54 + 12
➮ 48/66 { cut by 2 }
➮ 24/33 { cut by 3 }
➮ 8/11 or 8 : 11