Question

2. The numbers between 200 and 300, which when
divided by 6, 8 or 9 leaves remainder 8 in each
case, are
(a) 216.288
(b) 224, 296
(c) 210, 240
(d) 224, 288​

Answer 1

Answer:

answer is B 224 and 296

Step-by-step explanation:

• LCM of 6 ,8, and 9 is 72
• now 72 multiplied by 3 and 4 is 216 and 288
• As these numbers will be divisble by 6 ,8,9 add 8 in 216 and 288
• here is your answer 224 and 296

Answer 2

Given :  The numbers between 200 and 300, which when divided by 6, 8 or 9 leaves remainder 8 in each case

To Find : Numbers

(a) 216,288

(b) 224,296

(c) 210,240

(d) 224,288

e) 216 , 291

Solution:

Number = N

N = 6A  + 8

N = 8B + 8

N = 9C  + 8

=> N -  8  = 6A = 8B = 9C

=> LCM of 6 , 8  * 9  

=  72

N - 8  = 72K

=> N = 72K + 8

K     N = 72K + 8

224   ,  296

But Question is not correct because dividing by 6 will leave remainder 2 not 8

and divided by 8 will remainder 0  

      224   ,  296

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