2. The pair of equations x + 2y + 5 = 0 and –3x – 6y + 1 = 0 have
(A) a unique solution (B) exactly two solutions
(C) infinitely many solutions (D) no solution
Answers
Answer:
no solution
Step-by-step explanation:
The equations are:
x + 2y + 5 = 0
–3x – 6y + 1 = 0
a1 = 1; b1 = 2; c1 = 5
a2 = -3; b2 = -6; c2 = 1
a1/a2 = -1/3
b1/b2 = -2/6 = -1/3
c1/c2 = 5/1 = 5
Here,
a1/a2 = b1/b2 ≠ c1/c2
Therefore, the pair of equation has no solution
more doubts
1. If cos A = 4/5 , then the value of tan A is
(A) 3/5 (B) ¾ (C) 4/3 (D) 5/3
brainly.in/question/26614602
2. If sin A = ½ , then the value of cot A is
(A) √3 (B) 1/√3 (C) √3/2 (D) 1 brainly.in/question/26614602
3. The value of the expression [cosec (75° + θ) – sec (15° – θ) – tan (55° + θ) + cot (35° – θ)] is
(A) – 1 (B) 0 (C) 1 (D) 3 2
brainly.in/question/26614755
Answer:
no solution
Step-by-step explanation:
What would you like to
Exactly
The given equations are:
x+2y+5=0
−3x−6y+1=0
From the given equation we have:
a2a1=−31
b2b1=−62=−31
c2c1=15
⇒a2a1=b
HOPE IT IS HELPFULL
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