Question

2. the parallel sides of a trapezium are 21 and 18cm and the distance b/w them is 6.8cm , find the area of trapezoim?

Answer 1

☆ Given :

• Parallel sides of a trapezium = 21 cm and 18 cm.
• Distance between these parallel sides is 6.8 cm.

☆ To find :

• The area of trapezium.

☆ Solution :

We know that,

${\boxed{\sf{Area_{(trapezium)}={\cfrac{1}{2}}\times{h}(sum \ of \ parallel \ sides)}}}$

A/Q

$\to\sf{Area_{(trapezium)}=}\dfrac{1}{2}\times6.8(21+18)$

$\to\sf{Area_{(trapezium)}=}\dfrac{1}{2}\times6.8\times39$

$\to\sf{Area_{(trapezium)}=}\cfrac{1}{\cancel2}\times\cancel{265.2}^{132.6}$

$\to\sf{Area_(trapezium)=132.6cm^2}$

More Formulas :

• Area of square = side²
• Area of rectangle = l×b
• Area of parallelogram = b×h
• Area of triangle = b×h/2
• Area of circle = πr²

Answer 2

Given :-

→ Parallel sides of trapezium = 21cm and 18cm

→ Distance between them = 6.8cm

To find :-

→ Area of Trapezium

Formula used :-

→ Area = ½ × (Sum of parallel sides) × (Distance between them)

Solution :-

→ Area = ½ × (21 + 18) × (6.8)

→ Area = ½ × (39) × (6.8)

→ Area = ½ × 265.2

→ Area = 132.6

∴ The area of the trapezium = 132.6cm²

Learn more :-

→ Area of Rhombus =  ½ × Product of diagonals

→ Area of Parallelogram = Base × Height

→ Area of Square = side × side

→ Area of rectangle = Length ×  Breadth

→  Area of circle = πr²