Question

2. The perimeter of a semicircular garden is 180 m. Find the area of the garden. O
(1) 3850 m2
(2) 3350 m
(3) 2250 m
(4) 1925 m
leep was dug and the soil was spread​

Answer 1

Answer:

The correct option is 1 = 3850 m²

Explanation:

Given

Circumference of the semi-circular garden = 180 m

=> r (2+π) = 180

$= r = \frac{180}{(2 + \pi)}$

$= r = \frac{180}{2 + \frac{22}{7} }$

= r = 35 m

Area of the garden = πr²

$= \frac{22}{7} \times {35}^{2}$

$= \frac{22}{7} \times 1225$

= 3850 m²

Hope it helps!!