Question

2. The perimeter of a triangle ABC is 48 cm. If 4AB = 3BC and 5BC = 4AC, find the sides of the triangle. Hence, arrange the angles of the triangle in ascending order​

Answer 1

p=48cm

4AB=3BC

AB=3/4BC

5BC=4AC

AC=5/4BC

PERIMETER =AB+BC+AC

48=3/4BC+BC+5/4BC

48=3BC

BC=48/3

BC=16CM

AB=3/4BC

AB=0.75×16= 12cm

AC=5/4BC

AC=1.25×16=20CM

AB=12cm

BC=16cm

AC=20cm

AB<BC<AC