Question

2. The perimeter of a triangle is pp-p-2 and two of its sides are p-p+ 1 and
p2-2p+ 1. Find the third side of the triangle​

Answer 1

Answer:

The third side is (p-4) units

Step-by-step explanation:

Given :

The perimeter of a triangle is pp-p-2 and two of its sides are p-p+ 1 and p2-2p+ 1.

To find:

The third side of the triangle

Solution:

The perimeter of a triangle is pp-p-2= p^2-p-2

First side = p-p+1= 0+1=1

Second side = p^2-2p+1

Let the third side be X

As we know ,

Th perimeter of the triangle is the sum of all sides of the triangle

Perimeter= (1)+(p^2-2p+1)+X= p^2-p-2

=>p^2-p-2= p^2-2p+2+X

=>X=(p^2-p-2)-(p^2-2p+2)

=>X=(p^2-p^2)+(-p+2p)+(-2-2)

=>X=0+p+(-4)

=>X=p-4

The third side = p-4

Answer 2

Answer:

The third side is (p-4)...

Step-by-step explanation:

hope it's helpful