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The perimeter of the square ABCD is twice the perimeter of the triangle POR. If the sides
of the triangle are 21 cm 19 cm and 34 cm, find the length of each side of the square.
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Answer:
Sides of triangle are 21cm,19cm,34cm.
Perimeter of triangle is 21+19+34=54cm.
Perimeter of square is twice to the perimeter of triangle so 54×2=108cm.
We know that perimeter of square is 4×side.
Then
4×side = 108cm
Side=108/4=27cm
Hence solved
Step-by-step explanation:
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