Question

2. The perimeters of two similar triangles are 30 cm and 20 cm respectively. If one sided
the first triangle is 12 cm, determine the corresponding side of the second triangle​

Answer 1

Question

2. The perimeters of two similar triangles are 30 cm and 20 cm respectively. If one sided the first triangle is 12 cm, determine the corresponding side of the second triangle

Solution

Given :-

• The perimeters of two similar triangles are 30 cm and 20 cm
• one sided the first triangle is 12 cm

Find :-

• Corresponding Side of the Second triangle

Explanation

Since , the Ratio of the corresponding sides of the similar triangles is same as the ratio of the there perimeters .

Let ,

• First ∆ ABC , Where AB = 12 cm
• Second ∆ PQR , Where, Find PQ = ?

Hence,

==> AB/PQ = BC /QR = CA = RL = (perimeter of ∆ ABC )/(perimeter of ∆PQR)

==> 12/PQ = 30/20

==> 30 * PQ = 12 * 20

==> PQ = (12 * 20 )/30

==> PQ = (12 * 4)/6

==> PQ = 2 * 4

==> PQ = 8 cm

___________________________

Hence

• Corresponding Side(PQ) of ∆PQR be = 8 cm

_________________

Answer 2

hey_here is your answer,

We know, a/d = b/e = c/f = (a+b+c) / (d+e+f)

Therefore, for two similar triangles, if a, b & c are sides of the first triangle and d, e & f are corresponding sides of the second triangle then ratio of corresponding sides of the two similar triangles is equal to ratio of their perimeter.

Now, one side of the first triangle =12cm

Let the corresponding side of the second triangle =x

Also, perimeter of the first triangle =30cm

& perimeter of the second triangle =20cm

Therefore, 12/x =30/20

=> x = (12*20) / 30 =8cm