Question

2
.
The PH of a 2 litre solution of HNO is 4.7. The
Ka of HNO is 4 x 10-6 then calculate number of
mole of HNO, dissolved in 2 litre solution :-
(1) 2 x 10-4 mol
(2) 4 x 10-5 mol
(3) 10-5 mol
(4) 1 x 10-4 mol​

Answer 1

Answer:

(2) 4 × 10 ^5

Explanation:

pH = -log[H+]

[H+] = antilog pH

antilog 4 . 7

2 × 10^5 m

no. of moles per litre = 2× 10^5

i.e 2 litre soln. contain 4 × 10^5 moles

please mark me as a brainliest pleasee

Answer 2

Explanation:

PH is defined as concentration of [H+]