Question

2. The phase difference between two points separated by 0.8m in a wave of frequency 120Hz is /2.
Find the wave velocity.

plz help me to do this​

Answer 1

Answer:

384 m/s

Explanation:

phase difference=2π/LAMDA ×path difference. .π/2=(2π/ LAMDA) ×0.8. LAMDA=0.8m×4=3.2 m. velocity= LAMDA×V=3.2×120 = 384m/s