Question

2. The point A ( k, k-2 ) lies in the first
quadrant and the point does not lie on any
of the axis. Another point M (m, 2m-5) is
such that m is equal to the least possible
integer value of k, then point M lies in which
quadrant​

Answer 1

Answer:

it lies in the 1st quadrant

Step-by-step explanation:

A (k,k-2)

The point A does not lie on any axis. Therefore neither the ordinate nor abscissa can be 0.

The least value of k for which the result is not 0 is 3. This means that coordinates of the point A are (3,1) for the least value of k.

For point M the value of the variable m is equal to the least value of k. This means that m=k=3.

Therefore the coordinates of point M are (3,1).

(3,1) lies in the first quadrant.

HENCE POINT M LIES IN 1ST QUADRANT.

Answer 2

Answer:

it lies in the 1st quadrant

Step-by-step explanation:

$A (k,k-2)$

Point A does not lie on any axis. Therefore, neither the ordinate nor abscissa can be 0.

The least value of k for which the result is not 0 is 3. This means that the coordinates of point A are $(3,1)$ for the least value of k.

For point M the value of the variable m is equal to the least value of k. This means that $m=k=3$.

Therefore, the coordinates of point M are $(3,1)$

$(3,1)$ lies in the first quadrant.

HENCE, POINT M LIES IN 1st QUADRANT.

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