Question

2. The polynomial a'+b2-c-2ab on factorization gives
A.(a-b-c) (a+b+c)
B.(a-b+c) (a+b-c)
C.(a-b+c) (a-b-c)
D.(a-b-c) (a+b-c) with steps​

Answer 1

c (a-b+c)(a-b-c)

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Answer 2

Option C is correct

Break it down into parts:

a²+b²-2ab=(a-b)(a-b)

a²+b²-c²-2ab=(a-b)²-c²

Then, factor in c²:

(a-b)²-c²=((a-b)+c)((a-b)-c)

=(a-b+c)(a-b-c)

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