Question

2. The pop() and remove() are similar functions.
3. A = [] and A = list will produce the same​

Answer 1

2. The pop() and remove() methods are similar methods.

Yes, this is true, in terms of objective. Both are related to the removal of an element from a list.

However, they function differently.

Let's take an example to understand.

• Using the pop() method:

$>>> \tt List1 = ["This",\ "is",\ 548,\ 14,\ 0,\ "a",\ "test",\ 48]\\\\>>> List1.pop(2)\\\\548\\\\>>> print(List1)\\\\\tt \big["This",\ "is",\ 14,\ 0,\ "a",\ "test",\ 48 \big]$

As you can see, the pop() method works, when you give an index value in the brackets. The respective element at the given index position will be removed from the list and displayed in the shell.

In the example, we gave index value 2 to be popped. Element 548 was in position 2 and was hence removed.

If no index value is given in the brackets, the last element will be removed, and displayed in the next line.

$>>> \tt List1 = ["This",\ "is",\ 548,\ 14,\ 0,\ "a",\ "test",\ 48]\\\\>>> List1.pop()\\\\48\\\\>>> print(List1)\\\\\tt \big["This",\ "is",\ 14,\ 0,\ "a",\ "test" \big]$

• Using the remove() method:

$>>> \tt List1 = ["This",\ "is",\ 548,\ 14,\ 0,\ "a",\ "test",\ 48]\\\\>>> List1.remove("This")\\\\>>> print(List1)\\\\\tt \big["is",\ 14,\ 0,\ "a",\ "test",\ 48 \big]$

The remove() method works, when an element is given in the brackets. The respective element is then removed. Unlike the pop() method, it doesn't require index values, but the elements alone. It is advisable to use it if you are aware of the elements that are in the list.

If the given value element to be removed is not in the list, it will result in an error.

3. A = [] and A = list() will produce the same result.

Yes, this is true. Both methods are ways of declaring a list.