2. The population of a town is increasing at the rate of 10% per annum. If its present population
is 36300. find : 6) its population after 2 years. (ii) its population 2 years ago.
Answers
Answered by
11
(i) Population after two years 36300×110%×110%
= 36300×[110/100]×[110/100]
=36300×1.1×1.1
= 43923
(ii) Population before two years
36300×90%×90%
=36300×[90/100][90/100]
=36300×0.9×0.9
=290403
Answered by
20
Answer:population after 2year =P(1+r/100) ^2
36300×(1+10/100) ^2
36300×11/10×11/10
36300×121/100
=43923 answer
Population 2 years ago = P/(1+r/100) ^2
36300/(1+10/100)
36300×10/11×10/11
36300×100/121
=30000
Hence the population of a town 2years ago = 30000 answer
Step-by-step explanation:
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