Question

2.
The position of a particle with respect to time
t along yaxis is given by : y = 12 -2, where,
y is in metres and t is in seconds. When the
particle achieves maximum speed, the position of
the particle would be
(1) 64 m
(2) 40 m
(3) 16 m
(4) 32 m
​

Answer 1

Answer:

1. 64

Explanation:

First differentiate the equation wrt t. On differentiating position, we get velocity.

v = dx/dt = 24t - 6t²

Now, for max velocity, equate the equation to zero and solve. We get,

24t - 6t² = 0. From here, t = 4. So max velocity for the particle occurs at t = 4 seconds.

Substitute t = 4 in the given equation y = 12t² - 2t³. We get, y = 64.