2. The potential energy 'U' of a particle varies with distance x from a fixed origin as U = where A and B В are x? + B dimensional constant. Find the dimension of length in AB (A) 0004 (B) 0005 (C) 0006 (D) 0007
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Answer:
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Answer:
x= distance from a fixed origin
u=
x
2
+B
A
x
unit of B is same as x
2
. Unit of x
2
=[L
2
]
B=[L
2
]
u=
x
2
+B
[x
1/2
]A
A=
x
u(x
2
+B)
=
s
2
kgm
2
×
m
1/2
m
2
A=
s
2
kgm
7/2
A=[ML
7/2
T
−2
]
Dimensions of AB=[ML
7/2
T
−2
][L
2
]
Dimensions of AB=[ML
11/2
T
−2
]
Explanation:
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