Question

2.
The press plunger of a Bramah (hydraulic) press is 5 m2 in cross-section and is
employed to lift a load of mass 500 kg. What minimum force will be required to be
applied on the pump plunger if its cross-sectional area is 200 cm2?​

Answer 1

Answer:

20 Newton (N)

Explanation:

p(press hunger) = p(pump plunger)

therefore.  500*g/5

therefore . p = 100g.

now ,

  F = pa

  F = 100g*0.02

  F = 1000*0.02

  F = 20 Newton (N)

Answer 2

Answer:

actually exact answer is 19.6N

Explanation:

follow