Question

2: The pressure between the tyres of a car (a four wheeler) and the
road is 150000 N/m. What is the area of contact between the tyre and the road if
the car has a weight of 15000 N?
Solution. Pressure both
t
ofamond the mand - 1 -
9​

Answer 1

Explanation:

pressure=force/area of contact

150000N/m=15000N/area of contact

therefore,

area of contact=150000N/15000N*m

=150m

Answer 2

$\huge\mathrm{\underline\red{Answer}:-}$

• Pressure between the tyres of a car and the road = 150000 N/m².

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• Weight of the car = 15000 N .

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But , this weight is distributed over the four tyres of the car .

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So , weight of the car acting on each tyre = $\frac{15000 \: N}{4} = 3750 \: N$

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This weight acts as normal force or thrust exerted on the road by the tyre .

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Therefore , area of contact between the tyreand the road

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$= \frac{force}{pressure} = \frac{3750 \: N}{15000 \: N/m²} = 0.25m²\: Ans.$