Question

2
The prime factorization of a natural number(n) is 2 ^3x3^2 x 5^2x7 How many consecutive
zeroes will it have at the end of it justify your answer. ​

Answer 1

if the prime factorization of a natural number n is 2^3 x 3^2 x 5^2 x 7, then the number of consecutive zeroes are? As 2^2 will multiply with 5^2 to form 100 and thus 2 zeroes will occur consecutively.

Answer 2

Answer:

Step-by-step explanation:

f the prime factorization of a natural number n is 2^3 x 3^2 x 5^2 x 7, then the number of consecutive zeroes are? As 2^2 will multiply with 5^2 to form 100 and thus 2 zeroes will occur consecutively.