2) The product of two consecutive natural numbers is 31 less than the sum of their squares. Find the numbers.
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Answered by
1
x and x+1 be the two consecutive numbers
Step-by-step explanation:
a/q
x(x+1) = x2 + (x+1)2 -31
x2+x = x2 + x2 + 2x + 2 -31
x-2x = x2 -2
-x = x2 -2
x2+x-2 = 0
x2 + 2x -x -2 = 0
x(x+2)-1(x+2) = 0
(x-1)(x+2) = 0
x=1 , x=-2
So the numbers are are 1 and 2
I hope this will help u....if there is any problem ...comment
Answered by
1
sorry...........
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