Math, asked by arunimabose100, 9 months ago


2. The production of soap in a soap factory rose from 800000 to
976820 in 2 years. Find the growth rate per annum.​

Answers

Answered by anuskadash23
0

Answer:

976820-800000÷2 after that u can get per annumgrowth rate

Answered by biligiri
0

Answer:

given A = 976820 , P = 800000, n = 2, r= ?

976820 = 800000(1+r/100/)²

976820/800000 = (1+ r/100)²

97682/80000 = (1+r/100)²

48841/40000 = (1+r/100)²

(221/200)² = (1+r/100)²

as exponent are same on both sides, we can equate the bases

221/200 = 1+r/100

r/100 = 221/200 - 1

r/100 = 21/200

r = 21/200*100

r = 21/2

r = 10.5 %

growth rate is 10.5 %

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