2. The quadratic equation x2 + x + 1 = 0 has no real root
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Answered by
19
x^2+x+1=0
discriminant = b^2-4ac
= 1-4
=-3
so the given quadratic equation has imaginary roots( complex roots)
Answered by
19
Answer:
The given equation is x^2+x+1=0
This is of the form ax^2+ bx +c =0, where a =1 , b= 1 and c = 1.
:. D = b^2-4ac
= (1)^2 - 4×1×1
= 1- 4
= -3
No real roots = D < 0
= -3 < 0
HENCE, THE GIVEN EQUATION HAS NO REAL ROOTS.
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