2. The radii of two circles are 8 cm and 6 cm respectively. Find
the radius of the circle having area equal to the sum of the
areas of the two circles.
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the first circle area is 8cm squ
second circle area is 6c squ
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Given :-
- Radius of 1st Circle = 8cm
- Radius of 2nd Circle = 6cm
- The 3rd circle is having area equal to the sum of the areas of the two circles.
To Find :-
- Radius of the 3rd Circle.
Solution :-
⟾ Radius of 1st Circle = 8cm
- Area of 1st Circle = πr²
- Area of 1st Circle = π × (8)²
- Area of 1st Circle = π × 8 × 8
- Area of 1st Circle = 64π
⠀
⟾ Radius of 2nd Circle = 6cm
- Area of 2nd Circle = πr²
- Area of 2nd Circle = π × (6)²
- Area of 2nd Circle = π × 6 × 6
- Area of 2nd Circle = 36π
⠀
⟾ Total Area of Circles :
- Total Area = 1st + 2nd circle's area
- Total Area = 64π + 36π
- Total Area = 100π
⠀
⟾ Required Radius of 3rd Circle :
- Area of 3rd Circle = Total Area
- πr² = 100π
- r² = 100
- r = √100
- Radius = 10cm
⠀
∴ Required Radius of 3rd Circle is 10cm
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★ Additional Info :
Formulas Related to Circle:
- Circumference of Circle = 2πr
- Area of Circle = πr²
- Diameter of Circle = 2r
- Radius of Circle = D/2
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