Question

2.The ratio in which the x-axis divides the segment joining (3, 6) and (12, -3) is- (1 Point)

Answer 1

Answer:

hope it helps

Step-by-step explanation:

on x-axis y is 0

so, by section formula [mx2+nx1]/[m+n , my2+my1/m+n]

ratio be m:n

therefore , m(12)+n(3)/m+n , m(-3)+n(6)/m+n] = (x,0)

so

-3m+6n =0 [ since a,b = x,y so a=x and b = y]

6n = 3m

m/n = 1:2

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