2. The ratio of the length, breadth and height of a cuboid is 5:3:2. If its volume is 3750 cm?, find the length,
breadth and height of the cuboid.
on in rectangular in shane. It is 90 cm x 60 cm. How high it must be
Answers
Answer:
Let the length, breadth and height of the cuboid be 5x,3x and 2x respectively.
We know that the volume of the cuboid is l×b×h.
It is given that the volume of the cuboid is 35.937 m
3
, therefore,
35.937=5x×3x×2x
⇒30x
3
=35.937
⇒x
3
=
30
35.937
=1.197
⇒x=
3
1.197
⇒x=0.33
Therefore, the length l=5x=5×0.33=1.65, breadth b=3x=3×0.33=0.99 and height h=2x=2×0.33=0.66
Now, the total surface area of cuboid is 2(lb+bh+hl), therefore, the total surface area with length 1.65 m, breadth 0.99 m and height 0.66 m is:
A=2[(1.65×0.99)+(0.99×0.66)+(0.99×1.65)]=2(1.6335+0.6534+1.089)=2×3.3759=6.7518 m
2
Hence, the dimensions of cuboid is 1.65 m, 0.99 m and 0.66 m and the total surface area of cuboid is 6.7518 m
2
.
Answer:
ANSWER
Let the length, breadth and height of the cuboid be 5x,3x and 2x respectively.
We know that the volume of the cuboid is l×b×h.
It is given that the volume of the cuboid is 35.937 m
3
, therefore,
35.937=5x×3x×2x
⇒30x
3
=35.937
⇒x
3
=
30
35.937
=1.197
⇒x=
3
1.197
⇒x=0.33
Therefore, the length l=5x=5×0.33=1.65, breadth b=3x=3×0.33=0.99 and height h=2x=2×0.33=0.66
Now, the total surface area of cuboid is 2(lb+bh+hl), therefore, the total surface area with length 1.65 m, breadth 0.99 m and height 0.66 m is:
A=2[(1.65×0.99)+(0.99×0.66)+(0.99×1.65)]=2(1.6335+0.6534+1.089)=2×3.3759=6.7518 m
2
Hence, the dimensions of cuboid is 1.65 m, 0.99 m and 0.66 m and the total surface area of cuboid is 6.7518 m
ur answer