Math, asked by raunakrishu1700, 11 months ago

2. The ratio of two numbers is 11 : 15. The sum of 3 times the first number and twice the second number is 630. The H.C.F. of the number is

Answers

Answered by knjroopa
22

Answer:

30

Step-by-step explanation:

Given  

2. The ratio of two numbers is 11 : 15. The sum of 3 times the first number and twice the second number is 630. The H.C.F. of the number is

Given ratio is 11 : 15

Let the number be x.

According to question 3 times first number and 2 times second number will be

3(11) + 2(15)

= 33x + 30 x

So 63 x = 630

x = 10

Now the numbers are 33 (10) = 330 and 30 (10) = 300

So hcf of 330 and 300 will be

Factors of 330 = 2 x 3 x 5 x 11

Factors of 300 = 2 x 2 x 3 x 5 x 5  

So hcf will be 2 x 3 x 5 = 30

Answered by kailashking7381
0

Answer:

30

Step-by-step explanation:

Let 2 numbers are 11k and 15k

According to the question

3*11k+2*15k= 33k+30k

63k=630

k=10

33k=330,30k=300

H.C.F=330,300

2×3×5=30

So,Hcf=30

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