Question

2. The
reaction N2O5 —> 2 NO2 + ½ O2 has the rate law, rate = K [ N2O5 ]. if the rate constant is 6.2 × 10^minus⁶ /sec. if the in the beginning, n2o5 is 15 moles per litre. calculate the rate of reaction.
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Answer 1

Explanation:

please refer to the attached file

Answer 2

Answer:

Its a 1st Order Reaction

Rate=k[A]

So, Rate of reaction would be

Rate=6.2×10 −4×1.25

Rate=7.75×10^4 mol L −1 S −1

Explanation:

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