Question

2) The root of X2 + kx + k = 0 are real and equal, find k.





right answer hai. like karo. ​

Answer 1

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✪QUESTION✪:-

The root of x² + kx + k = 0 are real and equal, find k.

✪ANSWER✪:-

x² + kx + k = 0

it is in the form of ax² + bx + c = 0

here ,

• a = 1
• b = k
• c = k

Given that ,

the roots of the equations are real and equal

so,

➠∆ = 0

➠b² - 4ac = 0 [∆=b² - 4ac ]

➠k² - 4(1)(k) = 0

➠k² - 4k = 0

➠k² = 4k

➠$\boxed{\sf{k = 4}}$

sub/: k=4 in the equation ,

➠x² + kx + k = 0

➠x² + (4)x +4 = 0

➠$\boxed{\sf{x² + 4x +4 = 0}}$

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TYPES OF ROOTS OF THE EQUATION :

( based on ∆ value and nature )

There are three types

• Real and Equal roots ( ∆ = 0)
• Real and Unequal roots ( ∆ >0 )
• imaginary roots ( ∆<0 )